Question

How much sulphuric acid (98% by wt.) is needed in the preparation of 250 g of a 25% solution of the acid by weigh​

Answer 1

Answer:

98% by weight of solution means 98g of H

2

SO

4

is present in 100g of solution.

Volume of solution =

density of solution

mass of solution

=

(1.8×1000)g/L

100g

Volume of solution =

18

1

L

Per cent H

2

SO

4

w/v of solution = molarity =

volume of solution (in L)

number of moles of H

2

SO

4

Molarity =

volume of solution

given mass of H

2

SO

4

/ molar mass of H

2

SO

4

Molarity =

1/18

98/98

=18M

Answer 2

Explanation:

63.77gm of sulphuric acid is needed