Question

How much sulphuric acid can be obtained from 5 kg of pure sulpher?

Answer 1

H2SO4--->H2O+SO3+1/2O2
32 gm of sulphur gives 98 gm of H2SO4
5 gm of sulphur gives ?(let it be x)
=> 32*x=5*98
=>x=5*98/32
=>x=15.3125 gm
hence,15.3125 gm of H2SO4 is obtained from 5 gm of sulphur.

Answer 2

The amount of sulphuric acid obtained from 5 kg of pure sulphur is 15.31 kg.

Given:

Mass of S = 5 g  

To find:

Amount of sulphuric acid = ?

Solution:

The chemical reaction which involves the formation of sulphuric acid from sulphur is given below:

$2 \mathrm{S}+3 \mathrm{O}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{2} \mathrm{SO}_{4}$

The chemical formula for sulphuric acid is $H_2SO_4$ and the chemical formula for sulphur is S. When S reacts with water and oxygen it results the formation of sulphuric acid.

Molar mass of S = 32 g/mol  

Molar mass of Sulphuric acid = 98 g/mol  

From the reaction, we can understand that,  

2 moles of S = 2 moles of Sulphuric acid

So, we need to find the number of moles present in 5 kg of sulphur.

$\text {Number of moles in 5 kg of Sulphur} =\frac{\text { Mass }}{\text {Molar mass}}=\frac{5000}{32}=156.25\ moles$

Thus,

156.25 moles of sulphur = 156.25 moles of sulphuric acid

Now,

$\text {Mass} = \text {Moles} \times \text {Molar mass}$

$\text {Mass} = 156.25 \times 98$

$\Rightarrow \text {Mass} = 15312.5 \ g = 15.31 \ kg$