Question

How much thermal energy should be added to 3.45 g Ne in a 10 litre flask to raise the temperature from 0°C to 100°C. (Atomic weight Ne = 20.18)?

Answer 1

Use this formula nC(process)(dt) which is equal to heat , and here heat is converted into thermal energy

Here process is isochoric

So,

C(process) changes to C(isochoric)=3/2R for monoatomic gases

nC(isochoric)(dt)=(3.45/20.18)*(3/2*2)(100-0)=51.46 cal