Physics, asked by vanshikabaliyan170, 6 months ago

How much thrust and pressure a man of weigh 80 Kg exert on the ground if-
                 a.)  He is standing with one foot.
                 b.)  He is standing on both feet.
                 c.)  He is lying.​
Given area of the body of the man is 0.6 m2 and that of his feet is 80 cm2.​

Answers

Answered by yashikapandya
1

Explanation:

When the man is lying:

Pressure

=

Force

Area

Force

=

m

g

=

(

80 kg

9.81 m/s

2

)

=

784.8 N

P

=

784.8 N

0.6 m

2

=

1308 Pa

When the man is standing:

Pressure

=

Force

Area

The same force as above because of the same weight:

Force = 784.8 N

So

P

=

784.8 N

80

×

10

4

m

2

=

98 062.5 Pa

Note: Do not forget to convert

cm

2

to

m

2

!

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