How much thrust and pressure a man of weigh 80 Kg exert on the ground if-
a.) He is standing with one foot.
b.) He is standing on both feet.
c.) He is lying.
Given area of the body of the man is 0.6 m2 and that of his feet is 80 cm2.
Answers
Answered by
1
Explanation:
When the man is lying:
Pressure
=
Force
Area
Force
=
m
g
=
(
80 kg
⋅
9.81 m/s
2
)
=
784.8 N
P
=
784.8 N
0.6 m
2
=
1308 Pa
When the man is standing:
Pressure
=
Force
Area
The same force as above because of the same weight:
Force = 784.8 N
So
P
=
784.8 N
80
×
10
−
4
m
2
=
98 062.5 Pa
Note: Do not forget to convert
cm
2
to
m
2
!
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