How much thrust will be required to exert a pressure of 6000 Pa on an area of 4 cm²
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We know P=F/A
where, P=pressure, A=area and F=force(here, thrust)
Here given that P=6000 Pa
and A=4cm² = 0.04 m²
So, F=PA
F= 6000Pa×0.04 m²=240N
Therefore, 240 N of thrust will be required to exert a pressure of 6000 Pa on an area of 4cm².
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