How much time does a racer 'x' take running on a circular track of 440 metres in anticlockwise direction to meet another racer 'y' who runs at twice the speed of x and in the same direction if it is known that they start running from diametrically opposite ends and the speed of x is 19.8 kmph.
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Answered by
3
Answer:
Let the speed of A be ‘2s’ m/s. Speed of B = ‘s’ m/s
Relative speed between A and B = 2s – s = s m/s
Time taken for A to meet B = length of the track / relative speed between A and B = 800 / s = 3 minutes
=> 800 / s = 180
=> s = 800/180 m/s
So, time taken by A to finish the race = 7200 / 2*(800/180) = 7200 * 180 / 2*800 = 9 * 90 seconds = 810 seconds = 13.5 minutes
Answered by
0
Answer:
40 seconds
Explanation:
speed of x : speed of y = 1: 2
Sx /sy = 1/2 = 19.8 / sy
i.e ;Sy = 19.8 × 2 Kmph = 11 m/s
Sx = 19m8kmph = 5.5 m/s
Relative speed (RS ) = 11-4.5 = 5.5 m/s
diametrically opposite ends means distance btw them is 220 mts . so D=220
time taken = D/ RS = 220 /5.5 = 40 seconds
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