Question

How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial value
a)15 min
b)150 sec
c)15 hr
d)1.5 min
(please give me a explanation for this answer)​

Answer 1

Answer:

we know, half life of P-32 is 14.29 days

$\frac{1}{2} part \: will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of \: \frac{1}{2} ) = \frac{1}{4} \: will \: diintegrate \: in \: 14.29 \: days \\ (\frac{1}{2} of \: \frac{1}{4}) = \frac{1}{8} will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of\frac{1}{8} ) = \frac{1}{16} will \: disintegrate \: in \: 14.29 \: days \\ \frac{1}{2} of \: \frac{1}{16} = \frac{1}{32} will \: disintegrate \: in \: 14.29 \: days$

so, total time taken=(14.29×5) days=71.45 days