Question

How much time does the object take to travel a distance of 40m?​

Answer 1

Answer:

Initial velocity of the car u = 20 m/s

Final velocity of the car = 0 m/s

Distance s in which the car stops = 40 m

Using the relation: v² - u² = 2 a s, we have

0²(m/s)² - 20² (m/s)² = 2× a × 40 m

==> -400 ( m²/s² )= 80 a (m),

==> a = -5 m/s², ie the car decelerate @ 5 m/s²

Using the relation: v = u +a t, where v= 0 m/s; u = 20m/s, a = -5 m/s², we get on substituting various values,

0 = 20 - 5×t; ==> t = 4 second.

So it would take 4 second to stop the car.