How much time heater will take to increase the temperature of 100g water by 50°C, if resistance of heating
coil is 484 ohm and supply voltage is 220 V.ac
A) 210 S
B) 42 S
C) 200 S
D) 50 S
Answers
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1
Answer:
A)210 S
Explanation:
given,
M = 100g =100×10^-3kg
∆t = 50℃
R = 484
V = 220
I^2Rt =MS∆t
V^2/R^2 ×R ×t = MS∆t [I = V/R]
V^2/Rt = MS∆t
t = MS∆t/V^2 R
WKT, S = 4.2×10^3
t = 100× 4.2×10^3×50 / (220)^2 × 484
t = 210 S
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