how much time the satellite will take to complete one Revolution around the Earth if velocity of satellite is 3.14 km per second and its height above the Earth's surface is 3600 km radius of earth is 6400 km
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When recalling our knowledge about circular motion we can derive the below equation,
ω = 2π/T
T - Time taken to complete one circle (Time Period)
ω- Angular Velocity
We can arrange the above equation as below because we wanted to find the time period of the satellite,
T=2π/ω ---------- (1)
And also we can use the below equation to relate angular velocity and linear velocity, because the question provides us the linear velocity of the satellite,
V = rω
ω = V/r ₋₋₋₋₋₋₋₋₋ (2)
By substituting equation 2 to 1 we can get,
T = 2πr/V
= [2 x 3.14 x (6400 + 3600)]/3.14
- We have to take the r as radius of the earth + distance from earth's surface to the satellite.
- π = 3.14
T = 20,000 Seconds
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