How much time would it take for the sound of thunder to travel 2000 meters if sound travels a speed of 330 meter per second
Answers
Answered by
3
The time taken by the sound of thunder is 6.06 s
Further explanation
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
d = distance = m
v = speed = m / s
t = time = seconds
Sound of thunder travel 2000 meters with speed 330 m/s, so :
d = 2000 m
v = 330 m/s
then time needed :
T=d/v=6.06 sec
Further explanation
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
d = distance = m
v = speed = m / s
t = time = seconds
Sound of thunder travel 2000 meters with speed 330 m/s, so :
d = 2000 m
v = 330 m/s
then time needed :
T=d/v=6.06 sec
Answered by
2
Answer:
2000/330 = 6.06 seconds
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