How much total number of electrons present in 4.6 g of sodium
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No. of atoms×12 is the no. of electrons
moles of sodium=given mass/molecular mass
=4.6/23=0.2moles
no. of atoms in 0. 2 moles =0. 2× 6.022×10^23
no. of electrons =
0.2×6.022×10^23×12
=14.45×10^23 (approximately
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moles of sodium=given mass/molecular mass
=4.6/23=0.2moles
no. of atoms in 0. 2 moles =0. 2× 6.022×10^23
no. of electrons =
0.2×6.022×10^23×12
=14.45×10^23 (approximately
Read more on Brainly.in - https://brainly.in/question/6404899#readmore
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