how much two digit number are there between 6 and 102 which are divisible by 6?
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Tn=a+(n-1)d. [here a=12 Tn=96and d=12-6=6]
96=12+(n-1)6
16=n+1
so n=15
Tn=a+(n-1)d. [here a=12 Tn=96and d=12-6=6]
96=12+(n-1)6
16=n+1
so n=15
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It is divisible by 6
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