Question

how much volume of 0.1 N oxalic acid solution can be reduced by 250 g of 8 %(by mass ) kmno4 solution​

Answer 1

Explanation:

how much volume of 0.1 N oxalic acid solution can be reduced by 250 g of 8 %(by mass ) kmno4 solution

Answer 2

Answer:

The amount of volume needed is 6.3 liters

Explanation:

Given: Volume of 0.1 N oxalic acid solution can be reduced by 250 g of 8 % kmno4 solution​

To find: The amount of volume needed.

Solution:

Equivalent mass:

Equivalent mass is the mass of one equivalent of any substance.

It can be calculated as,

$Equivalent mass = \frac{Molecular mass}{Number of electrons gained or lost}$

Normality:

Normality is defined as a measure of concentration equal to the gram equivalent weight per liter of solution.

It can be calculated as,

$Normality = \frac{Gram equivalent weight of solute}{Volume of solution}$ =  $\frac{Weight}{Equivalent weight}$

⇒ $N_{1} V_{1} = N_{2} V_{2}$

⇒ 0.1 × V = $\frac{250 * 8}{100 * 31.6}$

⇒ 0.1  × V = $\frac{2000}{3160}$

⇒ 0.1  × V = 0.6329

⇒ V  = $\frac{0.329}{0.1}$

⇒ V  = 6.3

Volume = 6.3 liters

Final answer:

The amount of volume needed is 6.3 liters

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