How much volume of 10ml HCl should be diluted with water to prepare 2L of 5M HCl
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Explanation:
N1V1 = N2V2
10N HCL = 5N HCL
10xV1 = 5×2.00
V1 = 5× 2.00/10
1.00 Litre.............
Hope it helps.............
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