Question

how much volume of 11 MHCL has to be diluted with water to prepare 3M 400ml Hcl?​

Answer 1

Answer:

Using the given data, we can see that (1.5M)(V1)=(0.25M)(500mL) . Solving for V1 gives us approximately 83 mL of 1.5 M HCl solution.

Answer 2

Answer: 109.09 mL  of 11 M HCl solution volume  of 11 MHCL has to be diluted with water to prepare 3M 400ml Hcl

Explanation:

11 MHCL means it gives the concentration of hcl solution and here M is the molarity .

The equation of dilution is

M₁ ˣ V₁ = M₂ ˣ V₂

where M₁ is the initial molarity , V₁ is the initial volume , M₂ is the final molarity and  V₂ is the final volume

SO , M₁ = 11 M , M₂ = 3M , V₂ = 400 ml and let V₁ be x

now putting the values in equation of dilution we get ,

M₁ ˣ V₁ = M₂ ˣ V₂

11 × x =  3 × 400

11x = 1200

x = 1200/11

x = 109.09 ml

V₁ = 109.09 mL

109.09 mL of 11 M HCl solution volume  of 11 MHCL has to be diluted with water to prepare 3M 400ml Hcl

To know more about dilution from the  given link

https://brainly.in/question/983665

to know more about molarity from the given link

https://brainly.in/question/1159016

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