how much volume of 18 m and 4 m sulphuric acid must be mixed to get 1 litre of 8 m sulphuric
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How much volume of 18M & 4M sulphuric acid must be mixed to get 1litre of an 8M solution of sulphuric acid?
Solution
Let us take = x litres of 18 M sulphuric and y litres of 4M solution.
Now, finally we need 1 litre of 8M solution
So, x litre + y litre = L litre
Or x + y = 1 - (i)
and,
18
M
×
x
l
i
t
r
e
+
4
M
×
y
l
i
t
r
e
s
=
8
M
×
1
l
i
i
t
r
e
⇒
18
x
+
4
y
=
8
-(ii)
Solve (i) & (ii)
from (i),
x
+
y
=
1
⇒
4
x
+
4
y
=
4
(iii)
(ii) - (iii) 18x + 4y = 8
4
x
+
4
y
=
4
14
x
=
4
x
=
4
14
=
2
7
x
+
y
=
1
⇒
y
=
1
−
2
7
=
5
7
So, take 47 litre of 18 M &
5
7
litre of 4M
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