Chemistry, asked by Anonymous, 1 month ago

How much volume of 8moles H2SO4 is required to prepare 2liters of 2moles H2SO4 by Dilution law​

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Answered by Anonymous
1

Answer:

Dilution law

M1V1 = M2V2

M1 = 8,M2 = 2 & V2 = 2

M1V1 = M2V2 => 8×V1 = 2x2

V1 = 4/8 = 1/2 = 0.5L

V1 = 0.5L

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