How much volume of 8moles H2SO4 is required to prepare 2liters of 2moles H2SO4 by Dilution law
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Answer:
Dilution law
M1V1 = M2V2
M1 = 8,M2 = 2 & V2 = 2
M1V1 = M2V2 => 8×V1 = 2x2
V1 = 4/8 = 1/2 = 0.5L
V1 = 0.5L
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