Question

How much volume of carbon dioxide is released from 40 grams of $NaCO_{3}$ at STP ?​

Answer 1

Answer:

Explanation:

Correct option is

C

2.24 L

CaCO  

3

​

⟶CaO+CO  

2

​

 

1 mole of limestone gives 1 mole of carbon dioxide, i.e.

Amount of CO  

2

​

 given by 100 g of CaCO  

3

​

=22.4L

Amount of CO  

2

​

 given by 10 g of CaCO  

3

​

=  

100

22.4

​

×10=2.24L

Hence, the correct answer is 2.24 L.