How much volume of carbondioxide at stp is liberated by the
combustion of 100cc of propane (C3H8)
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Answer:
The balanced equation is :
CH4 + 2O2 → CO2 + 2H2O
1cm³ CH3 requires 2cm³ O2
5cm³ CH3 requires 10cm³ O2
2C2H4 + 3 O2 = 2 CO2 + 2 H2O
1cm³ C2H4 requires 3cm³ O2
5cm³ C2H4 requires 15cm³ O2
Total volume O2 required to combust 5cm3 of CH4 and 5cm3 of C2H4 = 25cm³.
Edits
You can follow the same method for 50cm³ of volume. I thought it was 5 cm³.
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