Chemistry, asked by skmuzahid0007, 4 months ago

How much volume of carbondioxide at stp is liberated by the
combustion of 100cc of propane (C3H8)​

Answers

Answered by bhakti4616
0

Answer:

The balanced equation is :

CH4 + 2O2 → CO2 + 2H2O

1cm³ CH3 requires 2cm³ O2

5cm³ CH3 requires 10cm³ O2

2C2H4 + 3 O2 = 2 CO2 + 2 H2O

1cm³ C2H4 requires 3cm³ O2

5cm³ C2H4 requires 15cm³ O2

Total volume O2 required to combust 5cm3 of CH4 and 5cm3 of C2H4 = 25cm³.

Edits

You can follow the same method for 50cm³ of volume. I thought it was 5 cm³.

Similar questions