How much volume of CO2 is produced when 4g of methane is burnt in presence of oxygen?
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Answered by
1
Answer:
volume of oxygen required is 11.2L
Explanation:
CH4 + 2O2 -> CO2 + 2H20
4g of methane has 4/16 = 0.25 moles
From the equation it is clear that 1 mole of CH4 requires 2 moles of O2
Thus 0.25 moles will require 0.5 moles of O2
1 mole of gas will occupy 22.4 L
thus 0.5 mole of gas will occupy 11.2 L
Thus volume of oxygen required is 11.2L
hope it helps!
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