how much volume of dioxygen will be required for complete computation 0.08 gram of methane correct answer only
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Answer:
0.26 g is the right answer.
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Answer:
1 mole of a gas occupies 22.4 L of a gas at STP. Since, the molecular weight of methane is 16 g, Therefore, at STP, 22.4 L corresponds to 16 g. 112 cm 3 or 0.112 L will correspond to 22.416 ×0.112=0.08g.
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