Question

how much volume of dioxygen will be required for the formation of 1.12l of nitric oxide​

Answer 1

Answer:

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Zn+HCl→ZnCl2+H2

When 65.38 grams of Zn reacts with HCl it forms 22.4 L of hydrogen gas.

If 3.25 grams of Zn reacts with HCl it forms xL of hydrogen gas.

X=65.383.25×22.4=1.11

Explanation:

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