how much volume of dioxygen will be required for the formation of 1.12l of nitric oxide
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Zn+HCl→ZnCl2+H2
When 65.38 grams of Zn reacts with HCl it forms 22.4 L of hydrogen gas.
If 3.25 grams of Zn reacts with HCl it forms xL of hydrogen gas.
X=65.383.25×22.4=1.11
Explanation:
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