Question

how much volume of Nitrogen required to prepare 44.8 g of NO at stp​

Answer 1

According to Avogadro's Law a gas will always have a volume of

22.4

L

m

o

l

at Standard Temperature and Pressure (STP).

To determine the volume of 2.3 kg of nitrogen gas we would need to convert the mass of nitrogen to moles and then covert moles to liters at STP.

We begin be converting the mass to moles.

2.3 kg of nitrogen is 2300 g.

2300

g

x

1

m

o

l

14.1

g

=

163.1

m

o

l

N

2

Now we can convert moles to liters.

163.1

m

o

l

N

2

x

22.4

L

1

m

o

l

=

3

,

653.4

L

N

2

I hope this was helpful.

Answer 2

Answer:According to Ideal Gas law One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).

So , we have 44.8 L of NO at STP = 2 mol of NO

=> N2 + O2 ----> 2 NO

So here We got that 2 mol of N2 gives 2 mol of NO

That's why we Require 2 mol of N2 to produce 2 mol of NO .

So ,  Volume of N2 = 2 mol at STP = 22.4 × 2  = 44.8 L

If mine is wrong then Report it to know me what My mistakes are