Question

how much volume of oxygen at stp is required to burn 4 g of methane gas completely

Answer 1

CH4 + 2O2 -> CO2 + 2H20

4g of methane has 4/16 = 0.25 moles

From the equation it is clear that 1 mole of CH4 requires 2 moles of O2

Thus 0.25 moles will require 0.5 moles of O2

1 mole of gas will occupy 22.4 L

thus 0.5 mole of gas will occupy 11.2 L

Thus volume of oxygen required is 11.2L

Answer 2

heya.. Friend

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