How much volume of oxygen gas is required to complete combustion of 2 l of ethylene gas?
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C2H2 +3/2 O2 --> CO2 + H2O
Since 1 mole of ethylene requires 1.5 mole of O2
22.4L of ethylene will require 33.6L of oxygen
Thus 2L of ethylene will require 3L of oxygen
Since 1 mole of ethylene requires 1.5 mole of O2
22.4L of ethylene will require 33.6L of oxygen
Thus 2L of ethylene will require 3L of oxygen
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