Question

How much volume of solid should be added in 300 ml of water to obtain a solution containing 80% by volume of solvent

Answer 1

Answer:

1200ml is the right answer

V1=solute

Answer 2

Answer:

Volume of solute = V1

Volume of solute = V1Volume of water = 300ml

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1We want an 80% solution, so

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1We want an 80% solution, soV1/(300 + V1) = 0.8

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1We want an 80% solution, soV1/(300 + V1) = 0.8V1 = 0.8(300 + V1) = 240 + 0.8V1

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1We want an 80% solution, soV1/(300 + V1) = 0.8V1 = 0.8(300 + V1) = 240 + 0.8V10.2V1 = 240, so V1 = 240/0.2 = 1200

Volume of solute = V1Volume of water = 300mlVolume of final solution = 300 + V1We want an 80% solution, soV1/(300 + V1) = 0.8V1 = 0.8(300 + V1) = 240 + 0.8V10.2V1 = 240, so V1 = 240/0.2 = 1200So, 1200ml of the solute is required...