how much water do you add to make the concentration 1% sugar syrup using 12g sugar
Answers
Answer:
You want the 12g of sugar to be 1% of the whole solution.
So, say you add xx grams of water. The solution will be composed of 12 grams of sugar and xx grams of water, for a total of 12+x12+x grams.
So, the ratio "sugar/total" will be
\dfrac{12}{12+x}
12+x
12
and we want this ratio to be 1%, i.e. 1/100:
\dfrac{12}{12+x}=\dfrac{1}{100}
12+x
12
=
100
1
Multiply both sides by 100 and 12+x12+x to get
1200 = 12+x1200=12+x
Subtract 12 from both sides:
x = 1188x=1188
So, a solution composed of 1188 grams of water and 12 grams of sugar will be 99% water and 1% sugar.
The next exercise is just the same: you can build and solve the following equation
\dfrac{99}{99+x} = \dfrac{3}{4}
99+x
99
=
4
3
(I used the fact that 75% is three quarters). You should find the solution x=33.
Step-by-step explanation:
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Answer:
The amount of water required to produce 1% sugar syrup from 12g sugar is 1.2L.
Step-by-step explanation:
What is the volume of water?
- Volume is the amount of space occupied by an object, whereas capacity is the ability of an object to hold a substance, such as a solid, liquid, or gas.
- The amount of water that must be added for a given weight of solution is expressed as weight by volume solution (w/v).
w/v (weight by volume percentage):
The grams of solute in 100 milliliters of solution are defined as the percent weight per volume.
This method determines the concentration of the solution.
The concentration given is 1%.
The sugar weight is 12g. Solvent volume = weight/concentration
V = 12/1 = 12 * 100 mL V = 1.2 L
To learn more about volume refer to :
https://brainly.in/question/6090095
https://brainly.in/question/18659039
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