how much water is to be added to 100ml of 2N HCl to make it N/5 HCl
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Answer:
Explanation:
M1V1 = M2V2
(0.1)(1000) = (12) (x)
x = (0.1) (1000) / 12
x = 8.3 ml
Therefore add 8.3 ml of 37% HCL to 1 liter of D5W or NS to create a 0.1N HCL solution.
---OR ---(Alternative calculation)
12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/ml.
Need 0.1 N = 0.1 M
0.1 M x 36.5 = 3.65 g/L = 3650 mg.
3650 mg / 438 mg = 8.33 ml*
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