Question

How much water is to be added to 72l of a mixture in which ornage juice and water in the ratio 7:2,so that the final mixture contents orange juice and water in ths the ratio 4:3

Answer 1

26 ml of water should be added so that the final mixture contents orange juice and water in the the ratio 4:3

Step-by-step explanation:

The ratio of  orange juice and water is 7: 2 in mixture of 72 ml

So, quantity of orange juice = $\frac{7}{9} \times 72$

                                              = $56$

Quantity of water juice = $\frac{2}{9} \times 72$

                                              = $16$

Let x be the amount of water should be added to that the final mixture contents orange juice and water in this the ratio 4:3

So, $\frac{56}{16+x}=\frac{4}{3}$

$56(3)=4(16+x)$

$168=64+4x$

$168=64+4x$

$168-64=4x$

$\frac{168-64}{4}=x$

$26=x$

Hence 26 ml of water should be added so that the final mixture contents orange juice and water in the the ratio 4:3