How much water is to be added to dilute 10ml of 10n hcl to make it decinormal?
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Milli moles of conc.HCl=milli moles of dil HCl
$10\times 10=V\times \large\frac{1}{10}$$\Rightarrow V=1000ml$
Thus 990ml of water should be added to 10ml on conc.HCl to get decinormal solution.
$10\times 10=V\times \large\frac{1}{10}$$\Rightarrow V=1000ml$
Thus 990ml of water should be added to 10ml on conc.HCl to get decinormal solution.
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Milli moles of conc.HCl=milli moles of dil HCl
10×10=V×11010×10=V×110⇒V=1000ml⇒V=1000ml
Thus 990ml of water should be added to 10ml on conc.HCl to get decinormal solution.
10×10=V×11010×10=V×110⇒V=1000ml⇒V=1000ml
Thus 990ml of water should be added to 10ml on conc.HCl to get decinormal solution.
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