Question

how much water must be added to 48 ml of alcohol to make a solution that contains 25% of alcohol

Answer 1

(48/x+48)*100=25

48*4=x+48

x=144ml

Answer 2

144 mL of water needs to be added to 48 mL of alcohol to make a solution that contains 25% of alcohol.

Given,

Volume of alcohol=48 mL

Volume of water=v.

To find,

the volume of water that is to be added to 48 ml of alcohol to make a solution that contains 25% of alcohol.

Solution:

• Volume percentage of any substance in a solution is defined as the volume of that substance in 100 mL of solution.
• Volume percentage of a substance is temperature dependent.

Volume percentage=(Volume of the substance/Volume of solution)x100.

Volume of alcohol in the solution=48 mL

Volume of water that needs to be added=v

Total volume of the solution=48+v.

Volume percentage=(Volume of the substance/Volume of solution)x100

$25=\frac{48}{48+v} X100\\\frac{25}{100} =\frac{48}{48+v}\\\frac{1}{4} =\frac{48}{48+v}\\48+v=48X4\\48+v=192\\v=192-48\\v=144 mL.$

The volume of water that needs to be added is 144 mL.

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