How much water should be added to 1 L of 1M KOH solution to make it 0.2M KOH solution?
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Answer:
5 L
Explanation:
M1 = 1M
M2 = 0.2 M
V1=1 L
V2=?
So by the formula=
M1V1 = M2V2
Keeping values. So
(1)(1) = (0.2)(V2)
V2 = 5 L
I hope the answer is helpful !
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