How much water should be added to 10 g of acetic acid?
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Let mass of water added is V L.
Molarity= 60V10=6V1
⇒[H+]=(KaM)1/2
⇒M=Ka[H+]2 [H+]=10−3;pKa=−logKa=4.74
∴M=1.8×10−5(10−3)2 ∴Ka=1.8×10−5
6V1=1.8×10−510−6⇒V=3L
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