How much water should be added to 200cc of semi normal solution of naoh to make it decinormal?
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13
N1V1 = N2V2
1/2*200 = 1/10*V2
V2 = 1000 ML
volume of water added = 1000-200 = 800 ans
1/2*200 = 1/10*V2
V2 = 1000 ML
volume of water added = 1000-200 = 800 ans
Answered by
0
Answer:
Explanation:
800 cc
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