Question

how much water should be mixed with 10 ml of ethyl alcohol so as to obtain 5% alcohol water solution

Answer 1

Answer:

(10/ x + 10)*100 = 10 %

10* 100 /10 = x +10

100- 10 = x

x = 90 gm of ethanol

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Answer 2

Answer:

190 mL

Explanation:

volume %age = volume of solute/volume of solution × 100

5 = 10/10+x × 100

5(10+x) = 1000

50 + 5x = 1000

5x = 1000-50

5x = 950

x = 950/5

= 190 mL

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