Question

How much water should be mixed with 40 ml of alcohol to obtain 12 % of alcohol.​

Answer 1

Answer:

Hence, 88 ml of water will be added to 12 ml of alcohol in order to prepare a concentration 12%.

Explanation:

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Answer 2

Volume of solute = 40 ml

Volume of solution = volume of solute + volume of solvent    

Volume of solvent = volume of solution – volume of solvent

= 100 – 40 = 60 ml

concentration=$\frac{volume of solute}{volume of solute+volume of solvent}$×100

40=$\frac{40}{40+x}$×100

x=60

Hence, 60ml of water will be added to 40 ml of alcohol in order to prepare a concentration 12%.