How much water will be required to prepare 20% aqueous salt solution by adding 10 g of common
salt?
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Answer:
How much water will be required to prepare 20% aqueous salt solution by adding 10 g of common salt.
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40 g of water will be required to prepare 20% aqueous salt solution by adding 10 g of common salt.
Given,
Weight by weight percentage=20%
Mass of common salt(NaCl)=10 g.
To find,
the amount of water required to prepare 20% aqueous salt solution by adding 10 g of common salt.
Solution:
- The concentration term here referred to is weight by weight percentage.
- Weight by weight percentage of a substance in a mixture or a solution is defined as the mass of that substance in 100 g of solution or mixture.
- Weight by weight percentage of a substance is temperature independent.
- Weight by weight percentage is also referred as mass by mass percentage.
- It is calculated as:
- %w/w=(Mass of the substance/Mass of the mixture or solution) x 100.
Let the mass of solvent required to prepare the solution be m.
Mass of the solution=Mass of solvent+Mass of solute
Mass of the solution=(m+10) g.
%w/w=(Mass of the substance/Mass of the mixture or solution) x 100
The amount of water required is 40 g.
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