How much water would be filled in a container of height 21 cm,so that it appears half filled to the observer when viewed from top of the container ( refractive index of water = 4/3)?
Answers
Answer: 12 cm
Explanation:
Height of the container is = 21 cm
Refractive index of water = 4/3
Let us assume the height of the water away from the top of the container be “x” cm, so that it appears to be half-filled to the observer.
Then, the actual or real height of the water would be “(21 - x)” cm.
Also, the apparent height (depth) would be the same as “x” cm .
We know, the formula for refractive index is given as,
Refractive index = (real height or depth) / (apparent height or depth)
⇒ 4/3 = (21-x) / x
⇒ 4x = 63 – 3x
⇒ 7x = 63
⇒ x = 9
Thus,
The real or actual height of the water upto which the container should be filled, so that it appears to be half-filled to the observer is,
= 21 – x
= 21 – 9
= 12 cm
Answer:
Height of the container is = 21 cm
Refractive index of water = 4/3
Let us assume the height of the water away from the top of the container be “x” cm, so that it appears to be half-filled to the observer.
Then, the actual or real height of the water would be “(21 - x)” cm.
Also, the apparent height (depth) would be the same as “x” cm .
We know, the formula for refractive index is given as,
Refractive index = (real height or depth) / (apparent height or depth)
⇒ 4/3 = (21-x) / x
⇒ 4x = 63 – 3x
⇒ 7x = 63
⇒ x = 9
Thus,
The real or actual height of the water upto which the container should be filled, so that it appears to be half-filled to the observer is,
= 21 – x
= 21 – 9
= 12 cm
Explanation: