How much waterwill be operated by a motor of 10hoursepower lift up to a hieght 3.8m/s
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Answered by
0
Answer:
How much waterwill be operated by a motor of 10hoursepower lift up to a hieght
Explanation:
Power = P = 1 HP = 746 W
Depth = d = 20 m
H = 10 + 20 = 30 m
Volume = V = 2238 l
Mass of water = m = m=density×volume=1kg/m
3
×2238m
3
=2238kg
t=
P
potentialEnergy
=
P
mgh
=
746W
2238kg×9.8m/s
2
×30m
=900s=
60
900
min=15min
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A motor is used to lift water from a well of depth 10 m and to fill water tank of volume 30 m ^3 10 minutes. The tank is at height of 20 m above ground. If 20
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