How much weight will be lost if 250 g of caco3 is heated intensely in the open air?
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The balanced chemical equation is CaCO
3
→CaO+CO
2
.
1 mole (100 g) of calcium carbonate on combustion produces 1 mol (56 g) of calcium oxide.
Thus, 28 g (0.5 mol) of calcium oxide will be produced by the combustion of 0.5 mol (50 g) of calcium carbonate.
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