How much will be the heat developed in in a bulb of resistance 920 Ω working for
3 minute at 230 V ?
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Resistance = 920 ohm
Time = 3 min or 180 sec
Voltage = 230 V
Heat produced = I^2×R×t
H = (V^2*t) / R. ( v = RI )
H = (230*230*180) / 920
H = 10350 w
Hence, heat produced in the bulb will be 10.35 kw
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