Question

How much will be the power of a 220 V,100 W electric bulb working at 110 V

Answer 1

Answer:-

p = 25 w

Given :-

v = 220

p = 100 w

To find :-

The power if the voltage is 110v.

Solution:-

First calculate the resistance of the electric bulb.

Power of electric bulb is given by :-

$\huge \boxed {P = \dfrac{V^2}{R}}$

Put the given value ,

→$100 = \dfrac{(220)^2}{R}$

→$100 R = 220 \times 220$

→$100 R = 48,400$

→$R = \dfrac{48,400}{100}$

→$R = 484 \Omega$

Now, If the voltage becomes 110v

Now, If the voltage becomes 110vThen,

R = 484$\Omega$

→$p = \dfrac{(110)^2}{484}$

→$p = \dfrac{12,100}{484}$

→$p = 25 w$

hence,

The new power will be 25 watt.

Answer 2

Answer:

Answer:-

p = 25 w

Given :-

v = 220

p = 100 w

To find :-

The power if the voltage is 110v.

Solution:-

First calculate the resistance of the electric bulb.

Power of electric bulb is given by :-

\huge \boxed {P = \dfrac{V^2}{R}}

P=

R

V

2

Put the given value ,

→100 = \dfrac{(220)^2}{R}100=

R

(220)

2

→100 R = 220 \times 220100R=220×220

→100 R = 48,400100R=48,400

→R = \dfrac{48,400}{100}R=

100

48,400

→R = 484 \text{\O}megaR=484Ømega

Now, If the voltage becomes 110v

Now, If the voltage becomes 110vThen,

R = 484\text{\O}megaØmega

→p = \dfrac{(110)^2}{484}p=

484

(110)

2

→p = \dfrac{12,100}{484}p=

484

12,100

→p = 25 wp=25w

hence,

The new power will be 25 watt.