Question

How much will the potential of Zn/Zn2+ change<br />the solution of Zn2+ is diluted 10 times<br />(1) increase by 0.03 V<br />(2) decreases by 0.03 V o noulos<br />(3) increases by 0.059 V<br />(4) decreases by 0.059 V​

Answer 1

Answer:0.0295

Explanation:

Zn-----≥Zn2+ +e–

E1=E0–0.059÷2 log(Zn2+)

E2=E0–0.059÷2 ×log(Zn2+)÷10

E2–E1=0.059÷2

=0.0295