Physics, asked by Hotbabe, 1 year ago

How much will the resistance change,if the diameter of wire is doubled. Solve.

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Class 10th electricity

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Answered by thesilentkiller
22
HI i am not sure of this answer but i guess the resistance will be 1/4

Hotbabe: How?
thesilentkiller: The area of cross section is inversely proportional to the resistace.. so if the area of the conductor increases the resistance will decrease and since the diameter of the wire id doubled the resistance will decrease by half twice hence 1/4
Hotbabe: I wanted the derivation kinda thing
Hotbabe: Thanks btw
thesilentkiller: length of the wire is L, resistivity is ρ and diameter is d. The resistance of the wire is R=4ρL ∕ (πd²). Now if the diameter is doubled then the new resistance is R’=4ρL∕(π(2d)²) =4ρL∕(4πd²) =0.25R. Hence we see that the resistance of the wire becomes 25% of original resistance. This result is showing that the resistance decreases as we increase the cross-section area keeping the length constant.
Hotbabe: Now it's copied
thesilentkiller: copied?
thesilentkiller: well yes from my note bk.
Answered by UNNA111QUEEN
9
we know that ,area of cross section is inversely proportional to the resistance of the conductor,so if the area of cross section increses the resistance decreases..
R=p/a
        
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