Question

How much work does a pulling force of 40N do on the 20Kg box in pulling it 8m across the smooth floor at a constant speed the pulling force is directed at 60 degree above the horizontal.

Answer 1

Answer:

Explanation:

As you know ,

Work done = Force × Displacement × cos theta

= 40×8× cos 60°

= 160 Joules

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Answer 2

The work done to pull the box is 160 J.

Explanation:

The work done on a box is given as

$W=Fdcos\theta$

Here F is the force acting on the box, d is its displacement and $\theta$ is the angle between force and the direction of the motion of the box.

Given F = 40 N, d = 8 m and $\theta=60^0$.

Substitute the given values, we get

$W=40N\times8m\times cos60$

$W=40N\times8m\times 0.5$

W = 160 J

Thus, the work done to pull the box is 160 J.

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