Question

How much work done in moving a charge of 2 coulombs from a point at 118 volts to a point at 128
explain me briefly
give me correct ans. pls​

Answer 1

Answer:

$\large\boxed{\sf{10\:J}}$

Explanation:

We have been given that,

A 2 C charge is moved from a point at 118 V to a point at 128 V.

We have to calculate the Work done in moving the charge.

Clearly, We have the conditon,

• Charge, Q = 2 C
• Change in potential, ∆V = 128-118 = 10 V
• Work done, w = ??

We know that, work done is given by formula,

• $\large \boxed{ \sf{w = \frac{1}{2} Q \triangle V}}$

Substituting the values, We get,

$\sf {= > w = \frac{1}{2} \times 2 \times 10} \\ \\ \sf {= > w = 10 \: J}$

Answer 2

Answer:

20J

Explanation:

Here, Potential Difference, V1 = 118V; V2 = 128V

So difference in potential = 10V

Now Potential Difference = Work Done / Charge

Thus Work Done = Potential Difference * Charge

                             = 10V * 2C

                             = 20J ANS