How much work had to be done in lifting 20 pieces of brick of weight 22.5N each through a height of 7m?
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Answered by
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work done to lift a piece of brick
w = mgh
w = 22.5 × 7
w = 157.5 joule
so work done to lift 20 pieces of bricks = 20 × 157.5 = 3150 joule
hope it helps
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w = mgh
w = 22.5 × 7
w = 157.5 joule
so work done to lift 20 pieces of bricks = 20 × 157.5 = 3150 joule
hope it helps
mark me as brainliest if it seems to be helpful
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Answered by
1
Hey!
Given,
Weight = Force = 22.5 N
Height = 7 m
We know,
W = P.E(Potential Energy)
W = mgh
W = 22.5/9.8 * 9.8 * 7 [Mass = weight/gravity]
W = 157.5 J
Hence, work done to lift 20 pieces = 20*157.5
= 3150 J
Given,
Weight = Force = 22.5 N
Height = 7 m
We know,
W = P.E(Potential Energy)
W = mgh
W = 22.5/9.8 * 9.8 * 7 [Mass = weight/gravity]
W = 157.5 J
Hence, work done to lift 20 pieces = 20*157.5
= 3150 J
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