Math, asked by sbqwb03, 6 hours ago

how much work is done by a man carrying 20kg covers 10m of distance on level road​

Answers

Answered by devanshisah01
0

Answer:

If you are talking about lifting a 20 kg mass against the acceleration of gravity (10 m/s/s) for 10 meters than the Work is 20 x 10 x 10 = 2000 J (a Joule is a kgm/s/s, check the units), but I think there are several problems with this question, making it unanswerable.

First, you don’t specify whether the mass is being lifted or moved horizontally or (unlikely, in a beginning physics course) some other direction. We only count the work if it is converted into potential gravitational energy in a conservative force, which only applies if it goes up (or down). IF your mass is moving horizontally the work is zero.

Second, if the body has an acceleration other than gravity (is this a box being pushed along a surface, for example?) then we need to know the acceleration at which it is being pushed to calculate the net Force (m x a). Work would be the Force applied multiplied by the Distance (10 m) over which it was applied)

Finally, I think it is more standard to say Work is done on the body, not by the body, unless I really don’t understand this question at all.

Step-by-step explanation:

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Answered by chaayamishra123
0

Answer:

Work done = Force × Displacement

\text { Work done }=m g h=20 \times 9.8 \times 1=196 \mathrm{J} Work done =mgh=20×9.8×1=196J

Thus the work done to lift the load is 196J.

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