Question

How much work is done by agent in
forcing 4m3 of water throug a pipe of
radius 2cm . If the difference pressure
at two ends of the pipe is 10° 6m^2

Answer 1

Answer:

W = 8 x 10^6 Joules

Explanation:

Given the area of pipe that water moved = 4

Pressure across the pipe = 10^6

Radius of the pipe = 2 cm

Formula for pressure

P = F / A

F  = 2 x 10^6

From this we calculate the force;

Now work done is equal to

W = F x distance

W = 2 x 10^6 x 4

W = 8 x 10^6 Joules

Answer 2

The work done is 80 KJ.

Explanation:

The pressure is given by the formula:

P = F/A

Where,

P = Pressure = 10⁶ N/m²

F = Force = ?

A = 4 m³

On substituting the values, we get,

10⁶ = F/4

∴ F = 4 × 10⁶ N

The work done is given by the formula:

W = F × D

Where,

D = Distance through which force acts = Radius of the pipe = 0.02 m

On substituting the values, we get,

W = 4 × 10⁶ × 0.02

∴ W = 80 KJ