How much work is done by agent in
forcing 4m3 of water throug a pipe of
radius 2cm . If the difference pressure
at two ends of the pipe is 10° 6m^2
Answers
Answered by
1
Answer:
W = 8 x 10^6 Joules
Explanation:
Given the area of pipe that water moved = 4
Pressure across the pipe = 10^6
Radius of the pipe = 2 cm
Formula for pressure
P = F / A
F = 2 x 10^6
From this we calculate the force;
Now work done is equal to
W = F x distance
W = 2 x 10^6 x 4
W = 8 x 10^6 Joules
Answered by
1
The work done is 80 KJ.
Explanation:
The pressure is given by the formula:
P = F/A
Where,
P = Pressure = 10⁶ N/m²
F = Force = ?
A = 4 m³
On substituting the values, we get,
10⁶ = F/4
∴ F = 4 × 10⁶ N
The work done is given by the formula:
W = F × D
Where,
D = Distance through which force acts = Radius of the pipe = 0.02 m
On substituting the values, we get,
W = 4 × 10⁶ × 0.02
∴ W = 80 KJ
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